Introduction to Diffusion
2026-01-14
Key ideas from last lecture:
After today’s lecture, you will be able to:
entropy balance: \[ \frac{ds}{dt} = -\nabla \cdot \vec{J}_s + \dot{\sigma} \]
entropy flux: \[ \vec{J}_s = \sum_i \frac{\psi_i}{T}\vec{J}_i \]
entropy production: \[ T\dot{\sigma} = -\sum_i \vec{J}_i \cdot \nabla \psi_i \ge 0 \]
We will show one example that has non-trivial solution to \(\dot{\sigma} = 0\)

Consider one chemical species with chemical potential \(\mu\)
Definition: \[ \mu = \left(\frac{\partial U}{\partial N}\right)_{S,V} \]
\(\mu\) represents energy cost of adding more molecules
Diffusion driven by gradients in \(\mu\)
See analog to a water tank in handwritten notes
Entropy production due to diffusion: \[ T\dot{\sigma} = -\vec{J}_m \cdot \nabla \mu \]
Linear law: \[ \vec{J}_m = -L_{MM}\nabla \mu \]
\(L_{MM}\): phenomenological mobility coefficient
See analog in handwritten notes
Force balance and drift velocity (\(M\): mobility): \[ v = M \nabla \mu \]
Mass flux: \[ \vec{J} = c v = -M c \nabla \mu \]
Diffusion coefficient: \[ D = M k_B T \]
See analog in handwritten notes
For constant \(T,P\): \[ \mu_i = \left(\frac{\partial G}{\partial N_i}\right)_{T,P} \]
Chemical potential in a mixture solution: \[ \mu_i = \mu_i^0 + k_B T \ln \gamma_i x_i \]
activity coefficient \(\gamma_i = 1\) for ideal solution (Raoult’s law)
Substitute \(\mu_i\) into flux. For species \(i\) \[ \vec{J} = -D \nabla c \]
Assumptions:
concentration gradient is a special case of \(\nabla \mu\)
Mass conservation (no source term) \[ \frac{\partial c}{\partial t} = -\nabla \cdot \vec{J} \]
Substitution: \[ \frac{\partial c}{\partial t} = \nabla \cdot (D \nabla c) \]
If \(D_i\) is constant: \[ \frac{\partial c}{\partial t} = D_i \nabla^2 c \]
1D equation: \[ \frac{\partial c}{\partial t} = D \frac{\partial^2 c}{\partial x^2} \]
Steady state: \[ \frac{\partial^2 c}{\partial x^2} = 0 \]
\(\nabla^2 c\) measures curvature (sort of…)
Steady state implies zero curvature
Transient diffusion requires nonzero curvature
Curvature and Second Derivative
concave profile: \[ \frac{d^2 c}{dx^2} < 0 \]
convex profile: \[ \frac{d^2 c}{dx^2} > 0 \]
curvature determines smoothing direction
Search for any youtube video with “diffusion experiment dye”
Can we verify whether the scenario seen is Ficknian diffusion?
Length \(L\) traveled in time \(t\):
What is typical \(D_{AB}\) in a liquid?
- Often \(D_{AB}\sim 10^{-9}\) to \(10^{-10}\,\mathrm{m^2/s}\)
Assuming \(D_{AB} = 10^{-10} \mathrm{m^2/s}\) \(v_{m} = 10^{-3} \mathrm{m/s}\)
1

Intrinsic and extrinsic mechanism in doped halides
Kinetic theory description
Chapman–Enskog result: \[ D \propto \frac{T^{3/2}}{P} \]
Collisions limit transport
Stokes–Einstein equation: \[ D = \frac{k_B T}{6\pi \eta r} \]
\(\eta\): viscosity
\(r\): particle radius
Is it accurate enough in polymer solutions?
As the previous example of diffusion + convection video shows, the measurement of diffusivity really depends on which reference frame we use.
Isotope tracer experiments
Lattice constraint: \[ c_i + c_i^* + c_v = \text{const} \]
Vacancy concentration often at equilibrium
Non-radioactive species: \[ J_i = -L_{ii}\frac{\partial (\mu_i - \mu_v)}{\partial x} -L_{i{i}^*}\frac{\partial (\mu_{i^*} - \mu_v)}{\partial x} \]
Radioactive species: \[ J_{i^*} = -L_{{i^*}{i}}\frac{\partial (\mu_{i} - \mu_v)}{\partial x} -L_{{i^*}{i^*}}\frac{\partial (\mu_{i^*} - \mu_v)}{\partial x} \]
Vacancy (zero-flux, why?): \[ J_v = 0 \]